Given 2x-y = - 6, find the value of the algebraic formula [(square of X + square of Y) - (square of X-Y) + 2Y (X-Y)] / 4Y without numbers
The original formula = (X & sup2; + Y & sup2; - X & sup2; + 2xy-y & sup2; + 2xy-2y & sup2;) / 4Y
=(4xy-2y²)/4y
=4x-2y
=2(2x-y)
=2×(-6)
=-12
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