In the equation y = ax square + BX + C, when x = 2, y = 3; when x = 0, y = 3; when x = 4, y equals 11. Find the value of y when x equals - 2 I have finished my homework
∵
4a+2b+c=3
c=3
16a+4b+c=11
∴4a+2b=0
16a+4b=8
It is arranged as 4A + 2B = 0
8a+2b=4 ②
② (1) 4A = 4
a=1
Substituting a = 1 into ① 4 + 2B = 0
b=-2
∴y=x²-2x+3
When x = - 2, y = 4 + 4 + 3 = 11
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