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In the equation y = ax square + BX + C, when x = - 1, y = 0; when x = 1, y = 2; when x = 2, y = 9. (1) find the value of a, B, C. (2) find the value of y when x is equal to half
Let; y = ax & # 178; + BX + C
When x = 1, y = - 4
2, when x = - 1, y = 0
3. When x = 2 and x = 0, the value of Y is equal
In y = ax & # 178; + BX + C respectively
We get a + B + C = - 4,
a-b+c=0,
4a+2b+c=c;
It is necessary to solve the above equations
a=1
b=-2
c=-3
Please accept
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