If 2x + y = 1, find the minimum value of x power of 4 + y power of 2

If 2x + y = 1, find the minimum value of x power of 4 + y power of 2

4^x+2^y
=(2²)^x+2^y
=2^2x+2^y
>=2 ^ (2x + y) under 2 radical
=2 under 2 root
So the minimum value is 2 under the root sign