Given the value of solution X and y of binary linear equations 2x + y = K + 3, x-2y = 2K is - 2, find the value of (k ^ 2) - 2K + 1 The sum of the values of X and Y is - 2

Given the value of solution X and y of binary linear equations 2x + y = K + 3, x-2y = 2K is - 2, find the value of (k ^ 2) - 2K + 1 The sum of the values of X and Y is - 2

Then we can solve it by combining x + y = - 2 with 2x + y = K + 3 and x-2y = 2K
First, change x-2y = 2K to k = x-2y / 2
Then take 2x + y = K + 3 to get 3x + 4Y = 6
And then, x + y = - 2 is used to form a system of equations, and x = - 14, y = 12
So k = - 19
Then you can find the value of (k ^ 2) - 2K + 1 (complete square meter?), and it's easy to find the square of 20
=400
It should be right to calculate miso De