Given a coefficient of the quadratic equation y = ax & # 178; + BX + C, how to find the quadratic function expression by knowing the coordinates of the upper two points on the image Just give me an example

Bring in the parameters to get the cubic equation about a, B, C. according to the two expressions and the known parameters, solve the remaining two parameters

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1. Given that the solution of binary linear equations ax + y = B, mx-y = n is x = 3, y = - 1, then the coordinates of the intersection point of the graph of the linear function y = - ax + B and y = mx-n are
2. If the two solutions of the bivariate linear equation K × - y = - B are × = 2, y = 0 × = 1, y = - 1, find the expression of the corresponding linear function
3. It is known that x = 2Y = - 1 is a set of solutions of binary linear equation AX-2 = - by, and the value of 4-2a + B is obtained
4. Ax + (B + 3) y = 6 is a bivariate linear equation about X and Y. then the range of a and B is?
5. If ax ＋ (B ＋ 3) y = 5 is a quadratic equation with respect to X and y, then the value range of a and B is:
6. If ax + (B + 3) y = 6 is a quadratic equation with respect to X and y, then the value range of a and B
7. Ax + (B + 1) y = 3 is a bivariate linear equation about X and y, then the value range of M and N is? Wrong. It's the value range of ab
8. If ax + (A-1) Y-7 = 0 is a bivariate linear equation about X, y, then the value range of a is Writing process
9. It is known that the two solutions of binary linear equation AX + by + 2 = 0 are respectively x = 1, y = 4, x = - 3, y = - 4. Please solve the following problems: (1) solve the equation; (2) represent all the solutions of the equation with images
10. It is known that x = 3Y = - 2 and x = 2Y = 1 are two solutions of the quadratic equation AX + by + 3 = 0, then the analytic expression of the linear function y = ax + B is It is known that x = 3, y = - 2 and x = 2, y = 1 are two solutions of binary linear equation AX + by + 3 = 0, then the analytic expression of primary function y = ax + B is
11. It is known that the two solutions of the bivariate linear equation y = KX + B about X and y are x = 3, y = 4, x = - 1, y = - 2
12. X = 1y = 2 and x = − 1y = 4 are the solutions of the equation y = KX + B, and the values of K and B can be obtained
13. Given that x = 2, y = - 1 and x = - 1, y = 2 are solutions of the equation y = KX + B, then the value of K is______ The value of B is______
14. Given (brace) x = 3, y = - 2, finding (brace) x = - 2, y = 3 is the solution of equation y = KX + B, finding the value of K and B
15. If (k ^ 2-4) XY + (K-2) x + (K + 1) y + 2k-1 = 0 is a quadratic equation with respect to X and y, then k =? HELP ME
16. If (K-4) x + (K-2) x + (K + 3) y = K + 1 is a quadratic equation with respect to XY, what is the value of K?
17. Given the value of solution X and y of binary linear equations 2x + y = K + 3, x-2y = 2K is - 2, find the value of (k ^ 2) - 2K + 1 The sum of the values of X and Y is - 2
18. It is known that the solution of the system of linear equations {2x-y = k, x-2y = 11-2k} with respect to X and Y satisfies X-Y = 2, and the value of K is obtained
19. To solve the equations: 0.5x-3y = - 1-12x + 5Y = 3
20. X / 2 + Y / 3 = 7 and 2x / 3-y / 4 = 1