Find the value range of the letter X in the algebraic formula [√ (x + 3) + √ (2-x)] / [(x-1) (x + 4)]
Because it is a non negative number under the root sign, so x + 3 ≥ 0, 2-x ≥ 0, we can get - 3 ≤ x ≤ 2, because [(x-1) (x + 4)] is a divisor, and the divisor cannot be 0, so x ≠ 1, X ≠ - 4, so the value range of X is - 3 ≤ x ≤ 2 and X ≠ 1
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