Prove: A & # 178; + B & # 178; + C & # 178; ≥ AB + BC + AC
First of all, add that this inequality must be a > 1, b > 1, C > 1
The original equation is changed into:
a²+b²+c²-ab-bc-ac≥0
2a²+2b²+2c²-2ab-2bc-2ac≥0
(a-b)²+(b-c)²+(a-c)²≥0
And ∵ (a-b) & # 178; ≥ 0, (B-C) & # 178; ≥ 0, (A-C) & # 178; ≥ 0,
The original inequality holds
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RELATED INFORMATIONS
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