Lx-y + 1L + (y + 5) = 0, xy = how much

Lx-y + 1L + (y + 5) = 0, xy = how much

lx-y+1l+(y+5)=0
So X-Y + 1 = 0, y + 5 = 0
So y = - 5
x=y-1=-6
So xy = 30