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Let's know the square of X + xy = 3, the square of XY + y = - 21. Find the square of X + 4xy + 3Y, the square of 2.2x-xy-3y
Because x ^ 2 + xy = 3 (1) XY + y ^ 2 = - 2 (2), so (1) + (2) has x ^ 2 + 2XY + y ^ 2 = 1, that is, (x + y) ^ 2 = 1 (1) - (2) has x ^ 2-y ^ 2 = 5 (1) x ^ 2 + 4xy + 3Y ^ 2 = (x ^ 2 + 2XY + y ^ 2) + 2 (XY + y ^ 2) = 1 + 2 * (- 2) = - 3 (2) 2x ^ 2-xy-3y ^ 2 = (x ^ 2 + 2XY ^ 2) + (x ^ 2-y ^ 2) - (3Y ^ 2 + 3xy) = (x + y ^ 2 -)
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