Given lx-1l + ly-3l = 0, find y + X of y-x. given that a is greater than 0, B is less than 0, and LAL is less than LBL, try to compare the sizes of a, - A, B, - B
Lx-1l + ly-3l = 0, then x = 1, y = 3, (y + x) / (Y-X) = 4 / 2 = 2, a > 0, so | a | = a, - a < 0 < A, B < 0, | B | = - B, | a | < B |, then a < - B, so - a > b, the result is B < - a < a < - B
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