If the squares of | A-3 | and (2B + 1) are opposite to each other, find the value of (B-1) (2 / 3-A) | Math enthusiast | Mathematical art

If the squares of | A-3 | and (2B + 1) are opposite to each other, find the value of (B-1) (2 / 3-A)

The sum of two opposite numbers equals 0 | A-3 | + (2B + 1) & sup2; = 0 because | A-3 | ≥ 0, (2B + 1) & sup2; ≥ 0, so | A-3 | = 0, (2B + 1) = 0, A-3 = 0, 2b + 1 = 0, a = 3, B = - 1 / 2 (B-1) [(2 / 3) - A] = [(- 1 / 2) - 1] × [(2 / 3) - 3] = (- 3 / 2) × (- 7 / 3) = 7 / 2

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