How to factorize x3-x2 + X + 1

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• 1. Factorization of X3 - X2 - X - 2
• 2. Let A2 + 2a-1 = 0, b4-2b2-1 = 0, and 1-ab2 ≠ 0 According to the condition of 1-ab2 ≠ 0, B2 = - A is obtained How did this step come about? Why B & # 178; = - a?
• 3. Factorization: (a2-2a + 2) 2 + 1 + 2 (- 2 + 2a-a2)
• 4. Factorization: (a ^ 2-3a) ^ 2 + 4A ^ 2-12a + 4=___________ n(n+1)(n+2)(n+3)+1=—————— (x^2-x)^2-8x^2+8x+12=_____________
• 5. Given 2x + 3Y = 5, if y is expressed by an algebraic expression containing x, then y=______ ．
• 6. Given that 3x + 2y-6 = 0, how much y = is obtained by using the algebraic expression y containing x
• 7. Let y in the quadratic equation 3x + 2Y = 6 be expressed as___ ．
• 8. If x = y + 3, then the value of algebraic formula 1 / 2 * (X-Y) + (Y-X) ^ 5 is
• 9. It is known that equation 3 (x-4) + 2 (y + 1) = 5. (1). Express y with the algebraic expression of X. (2) express x with the algebraic expression of Y
• 10. Given that x = 3 ^ (2m-1), y = 3 + 9 ^ m, please use the algebraic expression containing x to express y
• 11. A set a = {x | x2 + (2a-3) x-3a = 0, X ∈ r}, B = {x | x2 + (A-3) x + a2-3a = 0, X ∈ r} satisfies a ≠ B, and a ∩ B ≠ & # 8709;, and a ∪ B is represented by an example
• 12. Let a = {x ∣ x2 + (2a-3) x-3a = 0} B = {x ∣ x2 + (A-3) x + a2-3a = 0} if a ≠ B, a ∩ B = Ф find a ∪ B
• 13. Given a ∈ R, f (x) = x2; 3x-a2-3a. (1) when a = 4, solve the inequality f (x) > 0 (2) Let a = [- 8, - 4], the solution set of inequality f (x) > 0 be B, if a &; B, find the value range of real number a
• 14. f(x)=[(3a+2)x+1]/(x-2a). If the image of the inverse function of F (x) coincides with the image of y = f (x), find a Another: why is the symmetry center of y = f (x) image (2a, 3A + 2)? How to find the center of symmetry of a function?
• 15. Given that f (x) is an even function and an increasing function on (- ∞, 0), and the solution set of F (2a ^ 2-3a + 2) 0, find the real number m, n Count it out
• 16. Let a = {x | x2 + 4x = 0}, B = {x | x2 + 2 (a + 1) x + A2-1 = 0}, (1) if a ∩ B = B, find the value of A. (2) if a ∪ B = B, find the value of A
• 17. Let a = [x / x2 + 4x = 0}, B = {X / x2 + 2 (a + 1) + A2-1 = 0}. (1) if a ∩ B = B, find the value of A. (2) if a ∪ B = B, find the value of A X2 is the square of X, and A2 is also the square of A
• 18. Let a {x | x2 + 4x = 0}, B = {x | x2 + (2a + 1) x + A2-1 = 0} If B is contained in a, find the value of A &If a is contained in B, find the value of A If a is contained in B, find the value of a? The answer is a = 1, - 1 is not OK
• 19. Let a = {X / x2 + 4x = 0}, B = {X / x2 + 2 (a + 1) x + A2-1 = 0}, if a ∩ B = B, find the value of A Give me a process
• 20. How to factorize X2 - (a + A2) x + a3 < 0 How does it become (x-a) (x-a2) < 0