If x = y + 3, then the value of algebraic formula 1 / 2 * (X-Y) + (Y-X) ^ 5 is

X = y + 3, then X-Y = 3, x = y + 3, then Y-X = - 3, so 1 / 2 (X-Y) + (Y-X) ^ 5 = 1 / 2 × 3 + (- 3) ^ 5 = 1.5-243 = - 241.5, so 1 / 2 (X-Y) + (Y-X) ^ 5 = - 241.5

RELATED INFORMATIONS

1. It is known that equation 3 (x-4) + 2 (y + 1) = 5. (1). Express y with the algebraic expression of X. (2) express x with the algebraic expression of Y
2. Given that x = 3 ^ (2m-1), y = 3 + 9 ^ m, please use the algebraic expression containing x to express y
3. The equation x = 2m-1, y = 4-m, using the algebraic expression containing x to express y, then y=__________
4. Given the equation 2x + y = 3, if y is expressed by an algebraic expression containing x, then y=______ ．
5. If the algebraic expressions 3 (x-1) and (X-2) are opposite to each other, then x=
6. Given that the value of the second power + 5x + C of the algebraic formula 2x when x = 1 is 10, find the value of the algebraic formula when x = - 2
7. If 2x + 3Y = 4, try to find the value of the power X of the algebraic formula 4 and the power y of the algebraic formula 8
8. When x = 1 and x = - 4, the value of the algebraic formula ax ^ 2 + BX + C is 8. When x = - 1, the value of the algebraic formula ax ^ 2 + BX + C is 2. Find the value of a, B and C
9. If x = 1, the value of the algebraic formula ax ^ 2 + BX + 1 is 5. When x = - 1, the value of the algebraic formula ax ^ 3 + BX + 1 is obtained The first is ax ^ 2, the second is ax ^ 3
10. 0.7/x-0.03 / (0.17-0.2x) = 1 (find x,)
11. Let y in the quadratic equation 3x + 2Y = 6 be expressed as___ ．
12. Given that 3x + 2y-6 = 0, how much y = is obtained by using the algebraic expression y containing x
13. Given 2x + 3Y = 5, if y is expressed by an algebraic expression containing x, then y=______ ．
14. Factorization: (a ^ 2-3a) ^ 2 + 4A ^ 2-12a + 4=___________ n(n+1)(n+2)(n+3)+1=—————— (x^2-x)^2-8x^2+8x+12=_____________
15. Factorization: (a2-2a + 2) 2 + 1 + 2 (- 2 + 2a-a2)
16. Let A2 + 2a-1 = 0, b4-2b2-1 = 0, and 1-ab2 ≠ 0 According to the condition of 1-ab2 ≠ 0, B2 = - A is obtained How did this step come about? Why B & # 178; = - a?
17. Factorization of X3 - X2 - X - 2
18. How to factorize x3-x2 + X + 1
19. A set a = {x | x2 + (2a-3) x-3a = 0, X ∈ r}, B = {x | x2 + (A-3) x + a2-3a = 0, X ∈ r} satisfies a ≠ B, and a ∩ B ≠ & # 8709;, and a ∪ B is represented by an example
20. Let a = {x ∣ x2 + (2a-3) x-3a = 0} B = {x ∣ x2 + (A-3) x + a2-3a = 0} if a ≠ B, a ∩ B = Ф find a ∪ B