It is known that the solution of the equation 1 / 2 (1-x) = 1 + K and the solution of the equation 4 / 3 (3x + 2) = 10 / K-2 / 3 (x-1) about X are opposite to each other, and the value of K can be obtained

It is known that the solution of the equation 1 / 2 (1-x) = 1 + K and the solution of the equation 4 / 3 (3x + 2) = 10 / K-2 / 3 (x-1) about X are opposite to each other, and the value of K can be obtained

1 / 2 (1-x) = 1 + k1-x = 2 (1 + k) = 2 + 2kx = - 2k-14 / 3 (3x + 2) = 10k-2 / 3 (x-1) 3x + 2 = 3 / 4 [10k-2 / 3 (x-1)] 3x + 2 = 15K / 2-1 / 2 (x-1) 6x + 4 = 15K - (x-1) 7x = 15k-3x = 15K / 7-3 / 7, so 15K / 7-3 / 7 = - (- 2k-1) = 2K + 115k-3 = 14K + 7K = 10