As shown in the figure, in the diamond ABCD, ∠ ABC = 60 ° de ‖ AC intersects the extension line of BC at point E

Method 1: as shown in the right figure, connecting BD, ∵ quadrilateral ABCD is rhombic, ∵ ABC = 60 °, ∵ BD ⊥ AC, ∵ DBC = 30 °, ∵ de ⊥ AC, ∵ de ⊥ BD, that is, ∵ BDE = 90 °, ∵ de = 12be

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