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證明:法一:如右圖,連接BD,∵四邊形ABCD是菱形,∠ABC=60°,∴BD⊥AC,∠DBC=30°,∵DE‖AC,∴DE⊥BD,即∠BDE=90°,∴DE=12BE.法二:∵四邊形ABCD是菱形,∠ABC=60°,∴AD‖BC,AC=AD,∵AC‖DE,∴四邊形…
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