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用代入法. 設P(x,y),A(x1,y1), 則x=(x1+3)/2,y=(y1+0)/2, 解得x1=2x-3,y1=2y, 代入已知曲線方程得(2x-3)^2+(2y)^2=1, 化簡得(x-3/2)^2+y^2=1/4, 它是中心在(3/2,0),半徑為1/2的圓.
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