Given the set a = {x | 2a-1 ≤ x ≤ a + 1}, B = {x | x2-5x + 4 is greater than or equal to 0}, if a ∩ B is an empty set, then the value range of real number a is obtained

Given the set a = {x | 2a-1 ≤ x ≤ a + 1}, B = {x | x2-5x + 4 is greater than or equal to 0}, if a ∩ B is an empty set, then the value range of real number a is obtained

From the solution that x ^ 2-5x + 4 is greater than or equal to 0, we get that x ≥ 4 or X ≤ 1, because a ∩ B is an empty set
So: a + 11 (draw the number axis is easy to get), solution: A is empty set, you may copy the wrong question