The inequality f (2x-1) < f (3) solution set when f '(x) > 0 and y = f (x) are even functions when f (x) is derivable on R and X ∈ (0, + ∞)

Because the function f (x) is differentiable on R, when x ∈ (0, + ∞), f '(x) > 0
So the function f (x) can be derived on R and X ∈ (0, + ∞) increases monotonically
If y = f (x) is even, then | 2x-1|

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