If a * x * x + A * x + 1 > 0, the value range of a is obtained

If a * x * x + A * x + 1 > 0, the value range of a is obtained

The function f (x) = ax & sup2; + ax + 1 > 0 is always true, which shows that there is no intersection point between the function and X axis and the parabola opening is upward
That is, the equation AX & sup2; + ax + 1 = 0 has no real root,
So the discriminant A & sup2; - 4A < 0, a > 0 is required
The solution is 0 < a < 4
The answer is over