The fraction x2 + 2x of 1, when x takes what value is meaningful
(2x) / (x2 + 1) denominator cannot be equal to 0x2 + 1 ≠ 0x2 ≠ - 1, because x2 ≥ 0, so x takes any value
RELATED INFORMATIONS
- 1. For the fraction M-1 / x2-2x + m, no matter what the value of X is, the fraction is always meaningful
- 2. 8. Given that x2 + Y2 + 2x-6y + 10 = 0, then the values of X and y are respectively a.x = 1 and y = 3
- 3. If x2 + y2-2x-6y + 10 = 0, then 4 / (y + 1 / x)=
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- 7. Decomposition factor 7x & # 179; - 63x = (a + b) 178; + A + B = x ^ 4-81= There are three questions
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- 9. Find the inner common tangent equations of two circles X & # 178; + Y & # 178; = 16 and (x-3) + (y + 4) 178; = 1
- 10. Simplification (x ^ 2-2xy + y ^ 2-1) / (x-y-1)
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- 13. It is known that the function f (x) whose domain is r satisfies that f (f (x) - x2 + x) = f (x) - x2 + X has only one real number x0, such that f (x0) = x0 Why should the two values obtained from the analytic expression of function f (x) be rounded off x = 0?
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- 16. The known function f (x) = x-4x + A + 3, G (x) = MX + 5-2m 1: If y = f (x) has zero point on [- 1,1}, find the value range of real number a 2: When a = 2, if any x 1 belongs to [1,3], there is always x 2 belonging to [1,4], if f (x 1) = g (x 2) holds, then the value range of real number m is obtained
- 17. The analytic expression of F (x) by function f (2x) = 4x + 1
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