If x2-2x + 10 + Y2 + 6y = 0, find (2x + y) 2

x2-2x+10+y2+6y=0
x²-2x+1+y²+6y+9=0
(x-1)²+(y+3)²=0
x-1=0
y+3=0
∴x=1
y=-3
(2x+y)²=(2-3)²=1

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