With the four numbers of 0, 5, 8 and 7, we can form () different four digit numbers? (1) 10 (2) 18 (3) 11 (4) 9

With the four numbers of 0, 5, 8 and 7, we can form () different four digit numbers? (1) 10 (2) 18 (3) 11 (4) 9

This is a probability problem: 0 can't be the first place, so there are only five, eight and nine choices for a thousand, and a hundred can have three choices except for a thousand (at this time, 0 can be a hundred, and there are still two choices for four numbers except one used by a thousand), and a ten can have two choices (except for a hundred and a thousand, there are still two numbers left), so the answer is 3 * 3 * 2 * 1 = 18