Let a > 0b > 0, a square + b square - 6ab = 0, then a + B of B-A is equal to 0 | Math enthusiast | Mathematical art

Let a > 0b > 0, a square + b square - 6ab = 0, then a + B of B-A is equal to 0

A square + b square + 2Ab = 8ab. Both sides are square. Because they are positive numbers, there is no sign problem. So a + B = 2 square 2Ab. And because a square + B square-2ab = 4AB. I don't know whether a is big or B is big, so the square is signed. That is, B-A = 2 square AB or B-A = - 2 square ab

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