Let a be greater than B and greater than 0, and the square of a + the bungalow of b-6ab is equal to 0, then the value of a + B of A-B is obtained Square of a + square of B = 6ab, sharp,

A> B > 0; a & # 178; + B & # 178; - 6ab = 0, that is, a & # 178; + B & # 178; = 6ab (1) Because [(B-A) / (a + b)] &# 178; = (a-b) &# 178; / (a + b) &# 178; = (A & # 178; + B & # 178; - 2Ab) / (A & # 178; + B & # 178; + AB) (2) By substituting (1) into (2), we can get [(b

RELATED INFORMATIONS

1. (a + B of a-b - A-B of a + b) divided by (1 - a square - 2Ab + B of a square + b square)
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