Given the root 6a-12 + (2B + 2) square + / 6-4c / = 0, find the value of 2abc
Root 6a-12 > = 0
6a-12>=0,
(2B + 2) square > = 0
/6-4c/>=0
Root 6a-12 + (2B + 2) square + / 6-4c / = 0
∴6a-12=0,a=2
2b+2=0,b=-1
6-4c=0,c=1.5
2abc=2x2x(-1)x1.5=-6
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