A + B + C = 0 and the distance between B and - 1 is equal to the distance between C and - 1, find the square of a + 2b-c - (a-4c-b)

A + B + C = 0 and the distance between B and - 1 is equal to the distance between C and - 1, find the square of a + 2b-c - (a-4c-b)

If the distance between B, C and - 1 is equal, then B - (- 1) = - 1-C or C - (- 1) = - 1-B, then B + C = - 2. If a + B + C = 0, then a = 2. So: A & # 178; + 2b-c - (a-4c-b) = A & # 178; + 2b-c-a + 4C + B = A & # 178; - A + 3 (B + C) = 2 & # 178; - 2 + 3 × (- 2) = 4-2 + (- 6) = 4