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解:b,c與-1的距離相等,則b-(-1)=-1-c或c-(-1)=-1-b,得b+c=-2.又a+b+c=0,則:a=2.故:a²;+2b-c-(a-4c-b)=a²;+2b-c-a+4c+b=a²;-a+3(b+c)=2²;-2+3×(-2)=4-2+(-6)= -4
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