If a √ a + B √ B ＞ a √ B + B √ a, then the condition that real number a B should satisfy is

a√a +b√b＞a√b+b√a
Deformed
a(√a-√b)>b(√a-√b)
Because a ≥ 0, B ≥ 0
If a > b ≥ 0, the above formula is changed to a > B
If b > a ≥ 0, the above formula is changed to a

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