It is known that a, B, C belong to {positive real number}, and a ^ 2 + B ^ 2 = C ^ 2. When n belongs to N, n > 2, compare the size of C ^ n and a ^ n + B ^ n Very urgent
∵a^2+b^2=c^2
∴(a/c)^2+(b/c)^2=1
∴a/c<1,b/c<1
When n > 2,
(a/c)^n+(b/c)^n
<(a/c)^2+(b/c)^2=1
Thus a ^ n + B ^ n < C ^ n is obtained
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