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∵a^2+b^2=c^2 ∴(a/c)^2+(b/c)^2=1 ∴a/c<1,b/c<1 ∴當n>2時, (a/c)^n+(b/c)^n <(a/c)^2+(b/c)^2=1 從而得a^n+b^n<c^n
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