A, B and C are positive real numbers. Prove BC / A + AC / B + AB / C > = a + B + C

prove:
a,b,c>0
BC / A + AC / b > = 2 (BC / A * AC / b) = 2C
Similarly:
ac/b+ab/c>=2a
bc/a+ab/c>=2b
Add the three formulas
2(bc/a+ac/b+ab/c)>=2(a+b+c)
therefore
bc/a+ac/b+ab/c>=a+b+c

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