Known: 0 〈 a 〈 1, proof: 1 / a 4 / (1-A) greater than or equal to 9
Analysis method;
1/a 4/(1-a)=4/a(1-a)>=9
4/9
RELATED INFORMATIONS
- 1. It is proved that if a, B ∈ R, then at least one of a ^ 2 + AB and B ^ 2 + AB is non negative Good answer points
- 2. a. B is a non negative number √ (1-A ^ 2) √ (1-B ^ 2) = ab
- 3. If a > b > C, a + 2B + 3C = 0, AB > AC and ab
- 4. In space quadrilateral ABCD, ab ⊥ CD, BC ⊥ Da, prove: ab ^ 2 + CD ^ 2 = BC ^ 2 + Da ^ 2
- 5. If two points c and D outside the line BC are known, CA = CB, Da = dB, and the straight line CD intersects AB at O, then point O is the midpoint of AB, and CD is the vertical bisector of ab
- 6. It is known that C and D are points outside the line AB, and Ca = CB, Da = dB. It is proved that the straight line CD bisects AB vertically Prove with the vertical bisector of line segment
- 7. If we know the line AB and the points c, D, and Ca = CB, Da = dB, then the line CD is the integral of the line ab______ .
- 8. C. D is the point outside the line AB, and Ca = CB, Da = ab Please use the theorem of vertical bisector. No auxiliary line is allowed
- 9. As shown in the figure, D is a point in the quadrilateral aebc, connecting AD and BD. it is known that Ca = CB, Da = dB and EA = EB. (1) are the three points c, D and E in a straight line? Why? (2) If AB = 24, ad = 13, CA = 20, what is the length of CD?
- 10. As shown in the figure, (1) (2) Ca = CB, Da = dB, prove that CD is the vertical bisector of ab
- 11. Try to prove the inequality by analysis: (1 + 1 / sin ^ a) (1 + 1 / cos ^ a) > = 9
- 12. The proof of inequality in the second year of senior high school This is a thinking problem in my homework It is known that a > b > 0 (a-b)^2/8a
- 13. Analysis and synthesis to prove inequality If positive numbers a and B satisfy AB = a + B + 3, then the value range of AB is?
- 14. Senior high school mathematical inequality proof: when a > 0, b > 0, 1 / AB + 1 / a (a-b) > = 4 / A ^ 2
- 15. A + B = - 2 find the maximum value of ab Using inequality
- 16. Let f (x) = x2 + BX + 1, and f (- 1) = f (3), then the solution set of F (x) > 0 is () A. (-∞,-1)∪(3,+∞)B. RC. {x∈R|x≠1}D. {x∈R|x=1}
- 17. When a is a value, the solution of the equation a (3x-1) = 4x + 7 is positive, and when a is a value, the solution of the equation is in the interval [- 3,2]?
- 18. A & # 178; + B & # 178; + ab ≥ 0
- 19. In high school inequality, there is a common inequality ab ≤ [(a + b) / 2] 178; or ab ≤ (A & # 178; + B & # 178;) / 2 There is a common inequality in senior high school, which is ab ≤ [(a + b) / 2] 178; or ab ≤ (A & # 178; + B & # 178;) / 2. Is there any difference between [(a + b) / 2] 178; and (a & # 178; + B & # 178;) / 2, or is it equal?
- 20. The solution of inequality is 2 × & # 178; - 3 × - 2 ≤ 1?