When a is a value, the solution of the equation a (3x-1) = 4x + 7 is positive, and when a is a value, the solution of the equation is in the interval [- 3,2]?
a(3x-1)=4x+7
3ax-a=4x+7
3ax-4x=a+7
3a(x-4)=a+7
x=((a+7)/3a)-4
(1) Then ((a + 7) / 3a) - 4 > 0
(7-11a)/3a>0
Equivalent to (7-11a) (3a) > 0
So 0
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