It is proved that [2 [under radical (n + 1) - 1]] < 1 + 1 / radical 2 + 1 / radical 3 + +Thank you very much RT | Math enthusiast | Mathematical art

It is proved that [2 [under radical (n + 1) - 1]] < 1 + 1 / radical 2 + 1 / radical 3 + +Thank you very much RT

(1 △ radical n) = (2 △ 2 radical n) 2 * (radical n + 1-radical 1) = 2 * (radical (n + 1) - 1)

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