Solving logarithmic inequality Log (x + 1 is base, (x ^ 2 + X-6) ^ 2 is true) > = 4

Solving logarithmic inequality Log (x + 1 is base, (x ^ 2 + X-6) ^ 2 is true) > = 4

log(x+1)(x^2+x-6)^2>=4=log(x+1)(x+1)^4
When x + 1 > 1, x > 0
(x^2+x-6)^2>(x+1)^4
(x+3)^2(x-2)^2-((x+1)^2)^2>0
(x^2+x-6-x^2-2x-1)(x^2+x-6+x^2+2x+1)>0
(-x+5)(2x^2+3x-5)>0
(x-5)(x-1)(2x+5)

Elden Ring Premiere

RELATED INFORMATIONS