If | ab | = 4, then

RELATED INFORMATIONS

• 1. Through the right focus F of hyperbola x2-y2 = 1, make a straight line L with an inclination angle of 60 ° and intersect the hyperbola at two points a and B to find | ab|
• 2. If | ab | = 4, then such a line L has () A. 1 B. 2 C. 3 d. 4
• 3. If | ab | = 4, then such a line L has () A. 1 B. 2 C. 3 d. 4
• 4. It is known that the two focuses of hyperbola x ^ 2 - (y ^ 2 / 3) = 1 are F1 and F2 respectively. The slope of a straight line AB passing through the left focus F1 is 3. The area of rtabf2 is calculated Brother, your answer is wrong.
• 5. Through the right focus F of hyperbola C: x2-y23 = 1, make a straight line L intersecting hyperbola C at P and Q, OM = OP + OQ, then the trajectory equation of point m is______ ．
• 6. Through the left focus F1 of hyperbola X & sup2; - 3 / Y & sup2; = 1, make the chord AB with slope 2, find (1), the length of line AB; (2), set point F2 as the right focus
• 7. The straight line passing through the focus F1 of the hyperbola and the same branch of the hyperbola intersect at two points a and B, and | ab | = m, and the other focus F2, find the perimeter of the triangle abf2
• 8. It is known that the focus of the hyperbola x2 / 64-y2 / 36 = 1 is F1 and F2. The left branch of the straight line passing through the intersection of F1 hyperbola is at two points a and B, [AB] = m, and the circumference of the triangle abf2 is calculated All right, score [AB] is the absolute value of ab
• 9. The focal points of hyperbola x ^ 2 / 64-y ^ 2 / 36 = 1 are F1 and F2 respectively. The straight line L passes through the point F1, intersects two points a and B on the left branch of hyperbola, ab = m, and calculates the circumference of triangle abf2
• 10. The left and right focus of hyperbola x216 − Y29 = 1 are F1 and F2 respectively. The length of chord AB passing through point F1 on the left branch is 5, then the perimeter of △ abf2 is () A. 12B. 16C. 21D. 26
• 11. Given that the hyperbola x2 / 16-y2 / 9 = 1, the line L passing through its right focus f intersects the hyperbola ab. if | ab | = 5, then there are several lines L
• 12. The ellipse (x ^ 2) / 25 + (y ^ 2) / 9 = 1 passing through point a (8,1) intersects with two points P and Q to find the trajectory equation of the midpoint m of the chord PQ
• 13. If the line L and the ellipse x ^ 2 / 4 + y ^ 2 = 1 intersect at two points P and Q and l passes through the fixed point (1,0), then the trajectory equation of the middle point of the chord PQ is only solved by the great God
• 14. Find the trajectory equation of the midpoint of the parallel string with slope 2 in the ellipse X & # 178 / 16 + Y / 9 & # 178; = 1
• 15. Trajectory equation of the midpoint of a parallel chord with a slope of - 1 in ellipse x ^ 2 / 16 + y ^ 2 / 12 = 1
• 16. Given the vector a = (cosx / 2, SiNx / 2), B = (cosx / 2, cosx / 2), then f (x) = monotone increasing interval of a * B
• 17. Given that a and B are nonzero vectors and the function f (x) = (XA + b) (a-xb), a necessary and insufficient condition for the image of F (x) to be a parabola symmetric about the y-axis is A.a⊥b B. A parallel B C.|a|=|b| D.a=b
• 18. Let a and B be non-zero vectors. If f (x) = (XA + b) (a-xb), X belongs to R and is even, A. A vertical B B. a parallel B C. | a | = | B | D. | a | unequal | B|
• 19. a. B is a nonzero vector. "A ⊥ B" is "function f (x) = (XA + b) · (xb-a) is a linear function It is a necessary and insufficient condition,
• 20. It is known that a is a constant, and a > 0, vector M = (√ x, - 1), vector n = (1, ln (x + a)), Finding the maximum value of the function f (x) = m · n in the interval (0,1]