Through the left focus F1 of hyperbola X & sup2; - 3 / Y & sup2; = 1, make the chord AB with slope 2, find (1), the length of line AB; (2), set point F2 as the right focus
The equation of AB is y = 2 (x + 2), and the equation of AB is y = 2 (x + 2), and y = 2 (x + 2) (x + 2) is substituted into x \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\5 (25
RELATED INFORMATIONS
- 1. The straight line passing through the focus F1 of the hyperbola and the same branch of the hyperbola intersect at two points a and B, and | ab | = m, and the other focus F2, find the perimeter of the triangle abf2
- 2. It is known that the focus of the hyperbola x2 / 64-y2 / 36 = 1 is F1 and F2. The left branch of the straight line passing through the intersection of F1 hyperbola is at two points a and B, [AB] = m, and the circumference of the triangle abf2 is calculated All right, score [AB] is the absolute value of ab
- 3. The focal points of hyperbola x ^ 2 / 64-y ^ 2 / 36 = 1 are F1 and F2 respectively. The straight line L passes through the point F1, intersects two points a and B on the left branch of hyperbola, ab = m, and calculates the circumference of triangle abf2
- 4. The left and right focus of hyperbola x216 − Y29 = 1 are F1 and F2 respectively. The length of chord AB passing through point F1 on the left branch is 5, then the perimeter of △ abf2 is () A. 12B. 16C. 21D. 26
- 5. The two focal points of hyperbola y ^ 2 / 9-x ^ 2 / b ^ 2 = 1 are F1 and F2 respectively. If the length of chord AB passing through F1 is 4, the perimeter of triangle abf2 is 4
- 6. If the major axis of a hyperbola is 2a, F1 and F2 are its two focal points, and AF1, AB and BF2 form an arithmetic sequence, then AB equals () Why?
- 7. Given that the left and right focal points of hyperbola x ^ 2 / 64-y ^ 2 / 36 = 1 are F1 and F2 respectively, the straight line L passes through point F1, the left branch of intersection hyperbola is at two points a and B, and the absolute value of AB = m, the perimeter of triangle abf2 is calculated
- 8. It is known that F 1 F 2 is the focus of hyperbola ^ 2 / A ^ 2-y ^ 2 / b ^ 2 = 1 (a > 0, b > 0). The chord AB passes through F 1 and the two points of a and B are on the same branch if | af2 | + | BF2 | = 2 | ab| Then the value of | ab | is
- 9. Given that a focus of hyperbola x ^ 2 / A ^ 2-y ^ 2 = 1 coincides with the focus of parabola x = 1 / 8y ^ 2, what is the eccentricity of this hyperbola
- 10. It is known that the left focus of the hyperbola x ^ 2 / A ^ 2-y ^ 2 / b ^ 2 = 1 is f, the right vertex is a, the point P is on the hyperbola, and PF is perpendicular to the X axis, and the line AP intersects the Y axis at the point M. if the vector MP = 2, the vector am, what is the eccentricity of the hyperbola
- 11. Through the right focus F of hyperbola C: x2-y23 = 1, make a straight line L intersecting hyperbola C at P and Q, OM = OP + OQ, then the trajectory equation of point m is______ .
- 12. It is known that the two focuses of hyperbola x ^ 2 - (y ^ 2 / 3) = 1 are F1 and F2 respectively. The slope of a straight line AB passing through the left focus F1 is 3. The area of rtabf2 is calculated Brother, your answer is wrong.
- 13. If | ab | = 4, then such a line L has () A. 1 B. 2 C. 3 d. 4
- 14. If | ab | = 4, then such a line L has () A. 1 B. 2 C. 3 d. 4
- 15. Through the right focus F of hyperbola x2-y2 = 1, make a straight line L with an inclination angle of 60 ° and intersect the hyperbola at two points a and B to find | ab|
- 16. If | ab | = 4, then
- 17. Given that the hyperbola x2 / 16-y2 / 9 = 1, the line L passing through its right focus f intersects the hyperbola ab. if | ab | = 5, then there are several lines L
- 18. The ellipse (x ^ 2) / 25 + (y ^ 2) / 9 = 1 passing through point a (8,1) intersects with two points P and Q to find the trajectory equation of the midpoint m of the chord PQ
- 19. If the line L and the ellipse x ^ 2 / 4 + y ^ 2 = 1 intersect at two points P and Q and l passes through the fixed point (1,0), then the trajectory equation of the middle point of the chord PQ is only solved by the great God
- 20. Find the trajectory equation of the midpoint of the parallel string with slope 2 in the ellipse X & # 178 / 16 + Y / 9 & # 178; = 1