Vector a = (3, - 2), B = (- 2,1), C = (7, - 4) try a, B means C is vector!

RELATED INFORMATIONS

• 1. If a = (1,2), B = (- 1,0), C = (4,6) are given, and a and B are used to represent C, what is C
• 2. If the angle between vector a = (3, m, 4) and B = (- 2, 2, m) is obtuse, then the value range of M, please write the detailed process, the answer is m
• 3. Vector a (m, 2m), vector b (- - 3M, 2) if the angle between vector a and vector B is an obtuse angle, how can we solve the problem of the value range of M?
• 4. Given the vectors a = (x, 2) and B = (- 3, - 5), the angle between a and B is obtuse angle, find the value range of X
• 5. Given that a = (x, 2), B = (- 3, 5), and the angle between a and B is obtuse, then the value range of X is? Letter A. B is vector!
• 6. Given that vector a = (2, x), vector b = (3, 4), and the angle between vector a and vector B is obtuse, then the value range of X is___ A.x>-2/3 B. X > - 2 / 3 and X ≠ 8 / 3 C. X2 / 3 and X ≠ 8 / 3
• 7. Given the vector a = (a, 2), B = (- 3, 5), and the angle between vector a and vector B is obtuse angle, the value range of a is obtained Given the vector a = (in, - 2), B = (- 3,5), and the angle between a and B is obtuse, then the value range of in
• 8. Given the vector a = (E, 2), B = (- 3, 5), and the angle between a and B is obtuse, what is the value range of E,
• 9. The function of vector in Physics
• 10. How to transform rectangular coordinate velocity into polar coordinate velocity In a three-dimensional velocity field, it is necessary to decompose the velocity on a circular surface into radial velocity and tangential velocity We know how to use the dot product of vector to get the radial velocity, but we don't know how to get the tangential velocity. Because velocity has direction, we can't simply use Pythagorean theorem to get the tangential velocity Can you explain in detail how to find the tangent vector of the next derivative
• 11. Given the vector a = (5,10), B = (- 3, - 4), C = (5,0), let's use a and B to express the vector C
• 12. Given the vector a = (3, - 2) B = (- 2, - 1), C = (7, - 4), and C = λ a + μ B, what are the values of λ and μ
• 13. Given vector M = (2cos & # 178; X, √ 3) n = (1, sin2x) function f (x) = m * n (2) In the triangle ABC, ABC is the opposite side of the angle ABC and f (c) = 3, C = 1 and a > b > C respectively
• 14. We know the vector M = (2sinx / 2, - root 3), n = (1-2sin & # 178; X / 4, cosx), where x belongs to R 1. If M is perpendicular to N, find the set of values of X 2. If f (x) = m * n-2t, when x belongs to [0, π], the function f (x) has two zeros, and the value range of real number T is obtained
• 15. In the triangle ABC, the opposite sides of a, B and C are respectively a, B and C. The vector M = (COSA, 1) the vector n = (1,1-radical 3sina), and the vector m ⊥ n (1) finds the size of angle a (2) if B + C = radical 3A, finds the size of B and C
• 16. In △ ABC, the opposite sides of a, B and C are a, B and C respectively, the vector M = (COSA, 1), the vector n = (1,1-radical 3sina), and the vector m ⊥ the vector n, the size of a is calculated
• 17. It is known that a.b.c. is the three internal angles of a.b.c. the vector M = (- 2,1), n = (COS (a + π / 6), sin (a - π / 3)), and M is perpendicular to n Find the angle a if Sin & # 178; c-cos & # 178; C / (1-sin2c) = - 2, find the value of tanb
• 18. Let a and B be non-zero vectors and B = 1 vector a, and the angle between B is π / 4, then find Lim t → 0 (a + TB - a) / T
• 19. 1. Find the coordinate of the vector C whose module is root 2 and whose angle is equal to the vector a = (root 3, - 1) and B (1, root 3) (detailed steps are required)
• 20. Given the vectors a, B and C, | a | = 1 | B | = 2 | C | = 3, the angle between a ⊥ B, a and C is 60 ° and the angle between B and C is 30 ° find the length of vector a + B + C