Under the standard atmospheric pressure, the temperature is 40 ℃, the mass of 2kg water absorbs the heat of 5.46 times 10 to the fifth power Joule, how much does the water temperature increase? C water = 4.2 times 10 to the third power Joule / (kg ℃)

It can be calculated by the formula: q = C M (t2-t1), dividing the heat by 2 kg, and then dividing by 4.2 × 10 ∧ 3, the temperature difference is 65, so the temperature increases by 65 degrees,

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