Operate the ninth power of a (a > 0) according to the following requirements: if the index is odd, multiply by a; if the index is even, divide its index by 2. If this continues, how many times is the index of a 4? What is the result of a after the 100th operation?

If we ignore a and only look at the change of index, then obviously 9 - > 10 - > 5 - > 6 - > 3 - > 4 - > 2 - > 1 - > 2 - >... We can get the sixth step is 4, and then we notice that we finally get the 100th power of a between 1 and 2

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