We know that rational numbers a, B, C satisfy the absolute value of A-1 + the absolute value of B + 3 + the absolute value of 3c-1 = 0 Find the value of (ABC) to the 125th power / (a to the 9th power * B to the 3rd power * C to the 2nd power)

The absolute value is greater than or equal to 0
If the sum is 0, it is equal to 0
So A-1 = 0, B + 3 = 0.3c-1 = 0
a=1,b=-3,c=1/3
So ABC = - 1
The original formula = - 1 / (- 27 × 1 / 9) = 1 / 3

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