Given that a, B and C are rational numbers, and the square of (2a + 6) + | 0.25b-200 | + | C + 1 | = 0, find the value of 3A + 2B + 9C
The square of (2a + 6) + | 0.25b-200 | + | C + 1 | = 0 is the sum of non negative numbers, so each term is 0, so the square of (2a + 6) = 0, a = - 3; | 0.25b-200 | = 0, B = 800; | C + 1 | = 0, C = - 1.3A + 2B + 9C = - 9 + 1600-9 = 1582
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