If 8 (a + 2) square + 3 │ B-3 │ + 16 (c + 0.5) square = 0, find the square of (A's B power + 2C)
8 (a + 2) square + 3 │ B-3 │ + 16 (c + 0.5) square = 0 = = > A + 2 = 0, B-3 = 0, C + 0.5 = 0 = = > A = - 2, B = 3, C = - 0.5 (a ^ B + 2C) ^ 2 = [(- 2) ^ 3 + 2 * (- 0.5)] ^ 2 = [- 8 - 1] ^ 2 = 9 ^ 2 = 81
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