Given that a, B and C are three rational numbers, and ︱ ABC ︱ ABC, AC-B ︱ Oh, ︱ 2A + B ︱ 2A + B, a + B + C = 0, find a =?, B =?, C =? Oh = 0

Because ABC > ABC, ABC has 1 or 3 negative numbers;
Because AC-B > 0, AC must be positive and B may be positive and negative;
Because 2A + b > 2A + B, a must be positive, B may be positive and negative;
(calculated in this way)

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