Given the square of 8 (a + 2) + 3 | B-3 | + 16 (c + 0.5) = 0, find the value of the square of (A's B power + 2C) | Math enthusiast | Mathematical art

Given the square of 8 (a + 2) + 3 | B-3 | + 16 (c + 0.5) = 0, find the value of the square of (A's B power + 2C)

8 (a + 2) + 3 | B - 3 | + 16 (c + 0.5) = 0 because 8 (a + 2) ≥ 0,3 | B - 3 | ≥ 0,16 (c + 0.5) ≥ 0, so 8 (a + 2) = 0,3 | B - 3 | = 0,16 (C + 0.5) = 0, so a = - 2, B = 3, C = - 0.5, so (a ^ B + 2C) = (- 2) ^ 3 + 2 × (- 0.5)) =

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