若8(a+2)平方+3│b-3│+16(c+0.5)的平方=0,求(a的b次方+2c)的平方

若8(a+2)平方+3│b-3│+16(c+0.5)的平方=0,求(a的b次方+2c)的平方

8(a+2)平方+3│b-3│+16(c+0.5)的平方=0 ==> a+2 = 0,b -3 = 0,c +0.5 = 0 ==> a = -2,b = 3,c = -0.5(a^b + 2c)^2 = [(-2)^3 + 2 *(-0.5)]^2 = [-8 - 1]^2 = 9^2 = 81
記得採納啊