Given that the sum of squares of the two equations x ^ 2 + (M + 9) x + 2m + 6 = 0 is 24, what is the value of M

Given that the sum of squares of the two equations x ^ 2 + (M + 9) x + 2m + 6 = 0 is 24, what is the value of M

Let two of the equations x ^ 2 + (M + 9) x + 2m + 6 = 0 be x1. According to Weida's theorem, X2 is: X1 + x2 = - (M + 9), x1x2 = 2m + 6 ∵ the sum of squares of the two is 24 ∵ X1 & # 178; + x2 & # 178; = 24 and X1 & # 178; + x2 & # 178; = (x1 + x2) &# 178; - 2x1x2 = (M + 9) &# 178; - 2 (2m + 6) ∵ (M + 9) &# 178; - 2 (2m + 6) = 24 ∵