If the equation (M2 + 1) x-2m + 1 = 0 about X has a positive real solution, then the value range of M is

Obviously M & # 178; + 1 ≠ 0
Then the solution of the equation is x = (2m-1) / (M & # 178; + 1)
If the equation has positive real solution, then (2m-1) / (M & # 178; + 1) > 0
And M & # 178; + 1 ≥ 1 > 0
Only 2m-1 > 0 is required, that is, M > 1 / 2

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